5u^2+19u=6

Solution for 5u^2+19u=6 equation:

5u^2+19u=6

We move all terms to the left:

5u^2+19u-(6)=0

a = 5; b = 19; c = -6;
Δ = b2-4ac
Δ = 192-4·5·(-6)
Δ = 481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-\sqrt{481}}{2*5}=\frac{-19-\sqrt{481}}{10}
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+\sqrt{481}}{2*5}=\frac{-19+\sqrt{481}}{10}
$